CiviCRM Community Forums (archive)

Hello,

I have changed the User Language to es_ES (Spanish) and I want the Monetary Locale to be en_US format. But when I add one Membership to a contact and I see the civiContribute, the format has not been changed. If I change to the default user language, en_US, and the same Monetary Locale, then the format is correct. This happens with other user languages (i.e. German). Like to say, always use the User Language configuration, changes on the Monetary Locale don´t work.

Does anyone know what happens?

Thanks

It looks like the separation between the language locale and the monetary locale got lost when we were redesigning the configuration classes. This is issue CRM-2782, and I’ll work on it next week at the latest.

Once I fix this for CiviCRM 2.1, I’ll provide a patch for 2.0 in this thread.

I fixed this on trunk, which means this will be fixed in CiviCRM 2.1.

If you want to have this fixed in a CiviCRM 2.0 install, apply the following diff to your CRM/Core/BAO/Setting.php file:

Index: CRM/Core/BAO/Setting.php
===================================================================
--- CRM/Core/BAO/Setting.php (revision 13885)
+++ CRM/Core/BAO/Setting.php (working copy)
@@ -162,6 +162,9 @@
             //calculate hour var for Date Time
             $defaults['datetimeformatHourVar'] =  strstr($defaults['dateformatQfDatetime'], '%I') ?'h' : (strstr($defaults['dateformatQfDatetime'], '%l') ? 'g' : null);
 
+            // set proper monetary formatting, falling back to en_US and C (CRM-2782)
+            setlocale(LC_MONETARY, $defaults['lcMonetary'].'.utf8', $defaults['lcMonetary'], 'en_US.utf8', 'en_US', 'C');
+
             $skipVars = array( 'dsn', 'templateCompileDir',
                                'userFrameworkDSN',
                                'userFrameworkBaseURL', 'userFrameworkClass', 'userHookClass',

– in other words, add the line
setlocale(LC_MONETARY, $defaults['lcMonetary'].'.utf8', $defaults['lcMonetary'], 'en_US.utf8', 'en_US', 'C');
before the $skipVars = … line.